special relativity - Coulomb's Law- Why the Coulomb's law is valid …
The "traditional" form of Coulomb's law, explicitly the force between two point charges. To establish a similar relationship, you can use the integral form for a continuous charge distribution and calculate the field strength at a given point.
Coulomb's Law: why is $k = \\dfrac{1}{4\\pi\\epsilon_0}$
The 'reason' for the "$4\pi$" appearing here and in Coulomb's constant (believe it or not) so that Maxwell's equations can be written without any $4\pi$' factors! In order to understand this, consider how electrostatic phenomena are expressed in Coulombs law as "field intensity at a distance squared", compared to (the equivalent) Gauss' law ...
electromagnetism - Deriving Coulomb's Law from Gauss's Law
2016年12月20日 · You are correct that Gauss's law alone cannot be used to derive Coulomb's law. Instead, you need to supplement it with the hypothesis that space is isotropic, but nothing more. The thing is really in the language. You start with Gauss's law, and then you say "consider a point charge...", without actually saying much about what you mean by that.
electromagnetism - Is Coulomb's law accurate for moving charges ...
2014年7月15日 · Coulomb's law is not precisely true when charges are moving-the electrical forces depend also on the motions of the charges in a complicated way. One part of the force between moving charges we call the magnetic force. It is really one aspect of an electrical effect. That is why we call the subject "electromagnetism."
electromagnetism gauss-law coulombs-law - Physics Stack Exchange
Gauss' law and Coulomb's law are equivalent - meaning that they are one and the same thing. Either one of them can be derived from the other. The rigorous derivations can be found in any of the electrodynamics textbooks, for eg., Jackson. For eg., consider a point charge q.
Coulomb's law in vector forms? - Physics Stack Exchange
2016年10月25日 · The vector version of Coulomb's law is: $$\vec F_1=k\frac{q_1q_2}{r^2}\hat r_{21}$$ Note the difference in notation from your expression: $\vec F_1$ is the force felt by charge 1 . $\hat r_{21}$ is the unit vector from charge 2 towards 1 .
Coulomb's law and Gauss' Law - Physics Stack Exchange
2015年3月1日 · Because Gauss's law applies for both moving and stationary charges, while Coulomb's law applies only for stationary charges, Gauss's law can be considered more fundamental. This is why Gauss's law is one of the four Maxwell equations.
Generalized Coulomb's Law - Physics Stack Exchange
Coulomb's Law obeys Newton's third law - charges exert equal and opposite forces on each other under electrostatic conditions. The integral in the last expression you wrote down would evaluate to zero - it represents the total electrostatic force on a charge distribution, but there is no net electrostatic force on a charge distribution (under ...
Are the Maxwell's equations enough to derive the law of Coulomb?
Given the Gauss law AND the Lorentz force, yes it's possible to derive Coulomb's law as it already been answered. So I think the question is if it's possible to derive it given ONLY the four Maxwell equations (and not the Lorentz force). The answer is still yes since the Lorentz force is equivalent to the Faraday law and it can be derive from it.
Deriving Coulomb's law from quantum electrodynamics
2015年5月21日 · There are multiple ways to interpret Coulomb's law in quantum electrodynamics (QED). Interestingly, they don't lead to quite the same conclusion (but there is no inconsistency because they are not defined in the same way).